document.write( "Question 558711: The perimeter of a rectangle is 208 inches. The length exceeds the width by 52 inches. Find the length and the width. \n" ); document.write( "
Algebra.Com's Answer #363142 by oberobic(2304)\"\" \"About 
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P = 2*(L+W) = 208
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\n" ); document.write( "L+W = 208/2 = 104
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\n" ); document.write( "L = 104-W
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\n" ); document.write( "L = W+52
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\n" ); document.write( "L=L, so
\n" ); document.write( "104-W = W+52
\n" ); document.write( "52 = 2W
\n" ); document.write( "W = 26
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\n" ); document.write( "L = W+52 = 26+52 = 78
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\n" ); document.write( "Check answer with perimeter.
\n" ); document.write( "L+W = 26+78 = 104
\n" ); document.write( "P = 2*(L+W) = 2*104 = 208
\n" ); document.write( "Correct.
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\n" ); document.write( "Answer: L=78, W=26
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\n" ); document.write( "Done.
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