document.write( "Question 558711: The perimeter of a rectangle is 208 inches. The length exceeds the width by 52 inches. Find the length and the width. \n" ); document.write( "
Algebra.Com's Answer #363142 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! P = 2*(L+W) = 208 \n" ); document.write( ". \n" ); document.write( "L+W = 208/2 = 104 \n" ); document.write( ". \n" ); document.write( "L = 104-W \n" ); document.write( ". \n" ); document.write( "L = W+52 \n" ); document.write( ". \n" ); document.write( "L=L, so \n" ); document.write( "104-W = W+52 \n" ); document.write( "52 = 2W \n" ); document.write( "W = 26 \n" ); document.write( ". \n" ); document.write( "L = W+52 = 26+52 = 78 \n" ); document.write( ". \n" ); document.write( "Check answer with perimeter. \n" ); document.write( "L+W = 26+78 = 104 \n" ); document.write( "P = 2*(L+W) = 2*104 = 208 \n" ); document.write( "Correct. \n" ); document.write( ". \n" ); document.write( "Answer: L=78, W=26 \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |