document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=558675>Question 558675</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle is twice as long as it is wide.  If its length and width are both decreased by 4 cm, it's area is decreased by 164 cm2.  Find it's original dimensions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #363124 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=363124\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> width = w<BR>\n" );
document.write( "length = l\r<BR>\n" );
document.write( "\n" );
document.write( "l/w = 2<BR>\n" );
document.write( "l=2w<BR>\n" );
document.write( "Area = l*w<BR>\n" );
document.write( "=2w^2\r<BR>\n" );
document.write( "\n" );
document.write( "(l-4)*(w-4)= 2w^2-164<BR>\n" );
document.write( "(2w-4)(w-4)=2w^2-164<BR>\n" );
document.write( "2w^2-8w-4w+16=2w^2-164\r<BR>\n" );
document.write( "\n" );
document.write( "-12w=-180\r<BR>\n" );
document.write( "\n" );
document.write( "/12<BR>\n" );
document.write( "w=15cm<BR>\n" );
document.write( "length = 30cm<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );