document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=558479>Question 558479</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve this problem? not sure where to start<BR>\n" );
document.write( "9 Tan^2 x + 5 = 8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #363095 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=363095\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 9 Tan^2 x + 5 = 8<BR>\n" );
document.write( "9 Tan^2 x=3<BR>\n" );
document.write( "Tan^2 x=3/9=1/3<BR>\n" );
document.write( "Take sqrt of both sides<BR>\n" );
document.write( "Tan x=1/&#8730;3<BR>\n" );
document.write( "x=30º and  210º (in quadrants I and III where tan>0) (0 < x < 360º) </SPAN>\n" );
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