document.write( "Question 558393: can anyone solve these for me?\r
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document.write( "1) 5^(x+2)=8.5\r
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document.write( "2) 6.5^x = 8.4\r
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document.write( "i need to know what X is in both of these and the method for figuring them out please \r
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document.write( "thanks \n" );
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Algebra.Com's Answer #363074 by lwsshak3(11628) ![]() You can put this solution on YOUR website! Whenever you have the variable in the exponent, logs are needed to solve. \n" ); document.write( "1) 5^(x+2)=8.5 \n" ); document.write( "(x+2)log(5)=log(8.5) \n" ); document.write( "(x+2)=log(8.5)/log(5)≈1.3297 \n" ); document.write( "x=1.3297-2≈-.6703 \n" ); document.write( ".. \n" ); document.write( "2) 6.5^x = 8.4 \n" ); document.write( "x=log(8.4)/log(6.5) \n" ); document.write( "x≈1.137 \n" ); document.write( " \n" ); document.write( " |