document.write( "Question 558130: A passenger plane flew to moscow and back. The trip there took five hours and the trip back took nine hours. It averaged 144 km/h faster on the trip there than on the return trip. Find the passenger plane's average speed on the outbound trip.\r
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document.write( "O.k so I did have a go at it Trying to use a system of equations using the substitution method to eliminate one unknown but it didn't work. I will try and explain what I was playing around with:\r
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document.write( "D1 = Distance there D2 = Distance back ( but not sure if I needed this as it is same Distance )
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document.write( "Average Speed = S \r
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document.write( "D1/5 + D2/9 = S\r
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document.write( "D1/5 = D2/9+144 ( I tried substituting this in )\r
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document.write( "D2/9+144 + D2/9 = S ( then I combined the like terms )\r
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document.write( "D2/18+144 = s ( but this is where I realized I had failed as I still had 2 variables.\r
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document.write( "Please help me someone I am so bad at word problems and I would love to be confident at them. \r
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document.write( "P.S I wasn't sure about which was the outbound trip, I guessed it meant the trip back.\r
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Algebra.Com's Answer #363073 by KMST(5328)![]() ![]() You can put this solution on YOUR website! You almost had it, and then lost your sense of direction. \n" ); document.write( "You had \n" ); document.write( "So you could have written \n" ); document.write( "Having fractions/denominators makes it look hard, but you could have solved it to find \n" ); document.write( "D=1620 km \n" ); document.write( "Now you have the distance. You already had the times. \n" ); document.write( "The only question is the average speed in the outbound trip. I believe outbound is the trip going out there, to Moscow, so the time was 5 hours and the speed was 1620 km/5 h = 324km/h \n" ); document.write( " |