document.write( "Question 54056: Dear Sir
\n" ); document.write( "As a 72 year old, interested in numbers and algebra, but with very limited knowledge on the subject, I have been trying to algebraically solve the following problems, rather than by trial and error or a process of elimination.\r
\n" ); document.write( "\n" ); document.write( "abc=a+b+c, 1x2x3=1+2+3=6\r
\n" ); document.write( "\n" ); document.write( "abc=(a+b+c)² 8x16x72=(8+16+72)² 9216=96²\r
\n" ); document.write( "\n" ); document.write( "abcd=(a+b+c+d)² 2x4x6x12=(2+4+6+12)² 576=24²
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Algebra.Com's Answer #36305 by aaaaaaaa(138)\"\" \"About 
You can put this solution on YOUR website!
\"abc+=+a%2Bb%2Bc\"
\n" ); document.write( "\"abc+-+c+=+a%2Bb\"
\n" ); document.write( "\"c%28ab+-+1%29+=+a%2Bb\"
\n" ); document.write( "\"c+=+%28a%2Bb%29%2F%28ab+-+1%29\"\r
\n" ); document.write( "\n" ); document.write( "I will choose values for a and b arbitrarily. Suppose a = 6 and b = 2:\r
\n" ); document.write( "\n" ); document.write( "\"c+=+8%2F11\"
\n" ); document.write( "\"6%2B2%2B8%2F11+=+6%2A2%2A8%2F11\"\r
\n" ); document.write( "\n" ); document.write( "Therefore, we can choose any value for two of the values, and find a value for which this equation is true.\r
\n" ); document.write( "\n" ); document.write( "Similarly with all the other equations, as long as you don't restrict them to the naturals, and algebra isn't capable of that.
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