document.write( "Question 558308: Find the length of the chord of the ellipse {(x^2)/(a^2)}+{(y^2)/(b^2)}=1 directed along the diagonal of the rectangle constructed on the axes of the ellipse?
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Algebra.Com's Answer #363019 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "We need to find the distance between the two points where the green line\r\n" );
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document.write( "First find the equation of the green line:\r\n" );
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document.write( "It passes through the origin (0,0) and the point (a,b)\r\n" );
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document.write( "We find its slope:\r\n" );
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document.write( "m = \"%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\"\r\n" );
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document.write( "m = \"%28b-0%29%2F%28a-0%29\" = \"b%2Fa\"\r\n" );
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document.write( "Using the point-slope formula:\r\n" );
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document.write( "y - y1 = m(x - x1)\r\n" );
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document.write( "y - 0 = \"b%2Fa\"(x - 0)\r\n" );
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document.write( "y = \"a%2Fb\"x\r\n" );
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document.write( "To find the endpoints of the chord, where\r\n" );
document.write( "the green line intersects the red ellipse,\r\n" );
document.write( "we solve the system of equations:\r\n" );
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document.write( "\"system%28x%5E2%2Fa%5E2%2By%5E2%2Fb%5E2=1%2Cy=expr%28a%2Fb%29x%29\"\r\n" );
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document.write( "We clear each of fractions:\r\n" );
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document.write( "b²x² + a²y² = a²b²\r\n" );
document.write( "         ay = bx\r\n" );
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document.write( "Square both sides of the second equation:\r\n" );
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document.write( "       a²y² = b²x²\r\n" );
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document.write( "Substitute b²x² for a²y² in \r\n" );
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document.write( "b²x² + b²x² = a²b²\r\n" );
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document.write( "      2b²x² = a²b²\r\n" );
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document.write( "         x² = \"%28a%5E2b%5E2%29%2F%282b%5E2%29\"\r\n" );
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document.write( "         x² = \"a%5E2%2F2\"\r\n" );
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document.write( "          x = \"%22%22+%2B-+sqrt%28a%5E2%2F2%29\" \r\n" );
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document.write( "          x = \"%22%22+%2B-+a%2Fsqrt%282%29\"\r\n" );
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document.write( "          x = \"%22%22+%2B-+%28a%2Asqrt%282%29%29%2F2\" \r\n" );
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document.write( "Substitute a²y² for b²x² in \r\n" );
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document.write( "a²y² + a²y² = a²b²\r\n" );
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document.write( "      2a²y² = a²b²\r\n" );
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document.write( "         y² = \"%28a%5E2b%5E2%29%2F%282a%5E2%29\"\r\n" );
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document.write( "         y² = \"b%5E2%2F2\"\r\n" );
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document.write( "          y = \"%22%22+%2B-+sqrt%28b%5E2%2F2%29\" \r\n" );
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document.write( "          y = \"%22%22+%2B-+b%2Fsqrt%282%29\"\r\n" );
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document.write( "          y = \"%22%22+%2B-+%28b%2Asqrt%282%29%29%2F2\"\r\n" );
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document.write( "So the end points of the chord are\r\n" );
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document.write( " and  \r\n" );
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document.write( "We use the distance formula to find the length of the chord:\r\n" );
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document.write( "d = \"sqrt%28%28x%5B2%5D-x%5B1%5D%29%5E2%2B%28y%5B2%5D-y%5B1%5D%29%5E2%29\"\r\n" );
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document.write( "d = \r\n" );
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document.write( "d = \"sqrt%28%28a%2Asqrt%282%29%29%5E2%2B%28b%2Asqrt%282%29%29%5E2%29\"\r\n" );
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document.write( "d = \"sqrt%282a%5E2%2B2b%5E2%29\"\r\n" );
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document.write( "d = \"sqrt%282%28a%5E2%2Bb%5E2%29%29\"\r\n" );
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document.write( "That's it.\r\n" );
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document.write( "Edwin
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