document.write( "Question 552900: log(8x)-log(1+sqrtx)=2 \n" ); document.write( "
Algebra.Com's Answer #362999 by lwsshak3(11628)\"\" \"About 
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log(8x)-log(1+sqrtx)=2
\n" ); document.write( "log[8x/(1+√x)]=2
\n" ); document.write( "convert to exponential form
\n" ); document.write( "10^2=8x/(1+√x)=100
\n" ); document.write( "8x=100+100x^1/2
\n" ); document.write( "2x=25+25x^1/2
\n" ); document.write( "2x-25x^1/2-25=0
\n" ); document.write( "let u=x^1/2
\n" ); document.write( "u^2=x
\n" ); document.write( "2x^2-25u-25=0
\n" ); document.write( "By quadratic formula:
\n" ); document.write( "u=-0.930703=x^1/2 (reject, x^1/2>0)
\n" ); document.write( "or
\n" ); document.write( "u≈13.4307=x^1/2
\n" ); document.write( "x=u^2≈180.3837.. (ans)
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