document.write( "Question 558191: Cos 2x + cos x + 1= 0. Solve. \n" ); document.write( "
Algebra.Com's Answer #362971 by richard1234(7193)\"\" \"About 
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I presume you mean instead of .\r
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\n" ); document.write( "\n" ); document.write( "Using trig identities, we have\r
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\n" ); document.write( "\n" ); document.write( "Regroup this way:\r
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\n" ); document.write( "\n" ); document.write( "Now sin^2 - 1 is equal to -cos^2 x, so we have\r
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\n" ); document.write( "\n" ); document.write( "If cos x = 0 then x = pi/2, 3pi/2, 5pi/2, etc. Otherwise, we may divide by cos x to obtain\r
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\n" ); document.write( "\n" ); document.write( "We obtain x = 2pi/3, 4pi/3, 8pi/3, 10pi/3, ... or in general\r
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\n" ); document.write( "\n" ); document.write( " or or where k is any integer.
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