document.write( "Question 558082: a man has twenty coins consisting of dimes and quarters. if the dimes were quarters and the quarters were dimes, he would have ninety cents more than he has now...how many dimes and quarters does he have now? \n" ); document.write( "
Algebra.Com's Answer #362969 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let x = original number dimes \n" ); document.write( "Let y = original number of quarters \n" ); document.write( ": \n" ); document.write( "man has twenty coins consisting of dimes and quarters. \n" ); document.write( "x + y = 20 \n" ); document.write( ": \n" ); document.write( "if the dimes were quarters and the quarters were dimes, he would have ninety cents more than he has now. \n" ); document.write( "(10y + 25x) - (10x + 25y) = 90 \n" ); document.write( "10y + 25x - 10x - 25y = 90 \n" ); document.write( "25x - 10x + 10y - 25y = 90 \n" ); document.write( "15x - 15y = 90 \n" ); document.write( "simplify, divide by 15 \n" ); document.write( "x - y = 6 \n" ); document.write( "x + y = 20; added the 1st equation \n" ); document.write( "------------eliminates y find \n" ); document.write( "2x = 26 \n" ); document.write( "x = 13 dimes originally \n" ); document.write( "then \n" ); document.write( "20 - 13 = 7 quarters \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "See if that checks our \n" ); document.write( "13(25) + 7(10) = 395 \n" ); document.write( "13(10) + 7(25) = 305 \n" ); document.write( "---------------------- \n" ); document.write( "difference is 90\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "..how many dimes and quarters does he have now? 13, 7 \n" ); document.write( " |