document.write( "Question 558217: Hello again:\r
\n" ); document.write( "\n" ); document.write( " I was very pleased with your previous answer to a word problem you sent to me. This one is a little different but would like to also have a format to work future problems of the same.
\n" ); document.write( "this is the problem: Larry Mitchell invested part of his 40,000 advance at 4% annual simple interest and the rest 3% annual simple interest. If both account was 1,330 Find the amount invested at each rate
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Algebra.Com's Answer #362958 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Let x = the amount invested at 4% then the rest (40,000-x) is the amount invested at 3%. The earnings on these two amounts is given as 1,330.
\n" ); document.write( "This situation can be expressed by the following equation, after converting the percentages to their decimal equivalents:
\n" ); document.write( "0.04x+0.03(40,000-x) = 1,330 Simplify.
\n" ); document.write( "0.04x+1200-0.03x = 1,330
\n" ); document.write( "0.01x+1200 = 1,330 Subtract 1200 from both sides.
\n" ); document.write( "0.01x = 130 Divide both sides by 0.01
\n" ); document.write( "x = 13000 and 40,000-x = 27,000
\n" ); document.write( "Larry Mitchell invested 13,000 at 4% and 27,000 at 3%.
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