document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=558198>Question 558198</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Hello:<BR>\n" );
document.write( "please help me fiqure out this word problem for future math problems with the step to perform: i do recall this problems but it has been a while since i done this word math problem<BR>\n" );
document.write( "this is the problem: How much of an alloy that is 40% copper should be xixed with 500 ounce tha is 80% copper in order to get an alloy that is 60% copper. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #362943 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=362943\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 	percent	----------------	quantity							<BR>\n" );
document.write( "Alloy type I	80	----------------			500	ounce				<BR>\n" );
document.write( "Alloy type II	40	----------------			x	ounce				<BR>\n" );
document.write( "Mixture	60	----------------	500	+	x	ounce				<BR>\n" );
document.write( "										<BR>\n" );
document.write( "80*500+40x=60(500+x)<BR>\n" );
document.write( "40000+40x=30000+60x		<BR>\n" );
document.write( "40x-60	x=	30000		-40000			<BR>\n" );
document.write( "-20	x	=	-10000							<BR>\n" );
document.write( "/	-20									<BR>\n" );
document.write( "x=	500	ounce	of 	Alloy type II						<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );