document.write( "Question 558138: How many liters of a 30% alcohol solution must be mixed with 80 liters of a 90% solution to get a 80% solution \n" ); document.write( "
Algebra.Com's Answer #362937 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "Alcohol type I 90 ---------------- 80 liters
\n" ); document.write( "Alcohol type II 30 ---------------- x liters
\n" ); document.write( "Mixture 80 ---------------- 80 + x liters
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\n" ); document.write( "90*80+30x=80(80 +x)
\n" ); document.write( "7200+30x=6400+80x
\n" ); document.write( "30x-80x=6400-7200
\n" ); document.write( "-50 x = -800
\n" ); document.write( "/ -50
\n" ); document.write( "x= 16 liters of Alcohol type II
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