document.write( "Question 558138: How many liters of a 30% alcohol solution must be mixed with 80 liters of a 90% solution to get a 80% solution \n" ); document.write( "
Algebra.Com's Answer #362937 by mananth(16946)![]() ![]() You can put this solution on YOUR website! percent ---------------- quantity \n" ); document.write( "Alcohol type I 90 ---------------- 80 liters \n" ); document.write( "Alcohol type II 30 ---------------- x liters \n" ); document.write( "Mixture 80 ---------------- 80 + x liters \n" ); document.write( " \n" ); document.write( "90*80+30x=80(80 +x) \n" ); document.write( "7200+30x=6400+80x \n" ); document.write( "30x-80x=6400-7200 \n" ); document.write( "-50 x = -800 \n" ); document.write( "/ -50 \n" ); document.write( "x= 16 liters of Alcohol type II \n" ); document.write( " \n" ); document.write( " |