document.write( "Question 558170: I'm working with fraction exponents i.e. #roots. I know how to solve for the variable when it is an exponent, but this is a new lesson where I have to solve for the variable that is a base.
\n" ); document.write( " \"16d%5E%281%2F4%29=40\"
\n" ); document.write( "This what I've tried, but I've hit a dead end.
\n" ); document.write( "Problem: \"16d%5E%281%2F4%29%7D=40\"
\n" ); document.write( "Step 1: \"%284d%5E2%29%5E%281%2F4%29=%284%5E3-24%29\" or is it \"%284d%5E2%29%5E%281%2F4%29=%284%5E3%29-24\"
\n" ); document.write( " ---I got same bases on both sides of the equation and had 4^(3-24) subsitute my value for 40, since (4^3)=64, but I would have to subtract 24 from either the exponent or from the whole side of the equation. Here's where I hit a wall and I don't know what to do after that since I tried to do both of my alternatives.
\n" ); document.write( "P.S. This is an excercise to get our feet wet for tomorrow's lesson.
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Algebra.Com's Answer #362928 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
You don't want addition and/or subtraction. Stick to multiplication, division and powers.
\n" ); document.write( "First, division:
\n" ); document.write( "\"16d%5E%281%2F4%29=40\" --> \"d%5E%281%2F4%29=40%2F16\" --> \"d%5E%281%2F4%29=5%2F2\"
\n" ); document.write( "Now, powers:
\n" ); document.write( "\"d%5E%281%2F4%29=5%2F2\" --> \"%28d%5E%281%2F4%29%29%5E4=%285%2F2%29%5E4\" --> \"d=625%2F16\"
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