document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=558078>Question 558078</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Armond has two solutions available in the lab, one with 5% alcohol and another with 13% alcohol. How much of each solution should he mix together to obtain 6 gallons of a solution that contains 8% alcohol. \r<BR>\n" );
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document.write( "I have no idea where to even begin on this problem... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #362902 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=362902\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Armond has two solutions available in the lab, one with 5% alcohol and another with 13% alcohol. How much of each solution should he mix together to obtain 6 gallons of a solution that contains 8% alcohol. <BR>\n" );
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document.write( "alcohol + alcohol = alcohol<BR>\n" );
document.write( "0.06x + 0.13(6-x) = 0.08*6<BR>\n" );
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document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "6x + 13*6 - 13x = 8*6<BR>\n" );
document.write( "-7x = -5*6<BR>\n" );
document.write( "x = 30/7<BR>\n" );
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document.write( "x = 4 2/7 gallons (amt. of 6% solution)<BR>\n" );
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document.write( "6-x = 1 5/7 gallons (amt. of 13% solution)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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