document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=6524>Question 6524</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Where is the center of 25(x+5)^2 + 4(y-3)^2 = 100 ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #3629 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=3629\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Zero out the (x+5), which gives you x=-5, and zero out the (y-3), which gives you y=3.  The center of this (it is an ellipse) is at the point (-5,3).\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "R^2 at SCC </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );