document.write( "Question 557922: Where does the -16 come from in the vertical motion formula? \n" ); document.write( "
Algebra.Com's Answer #362851 by richard1234(7193)\"\" \"About 
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Good question. Start with the general equation for vertical motion:\r
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\n" ); document.write( "\n" ); document.write( " where a is the acceleration due to gravity.\r
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\n" ); document.write( "\n" ); document.write( "This equation can be derived using integral calculus (I'll prove it next). The acceleration due to gravity can be derived from the equation\r
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\n" ); document.write( "\n" ); document.write( " where G is the gravitation constant, m1 and m2 are the masses of some object and Earth respectively, and R is the radius of the Earth. Plugging in, we find that a is approximately -9.8 m/s^2 (about -32 ft/s^2). Half of that is -16 ft/s^2, which is where the -16 comes from.\r
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\n" ); document.write( "\n" ); document.write( "To derive the vertical motion formula, start with the fact that\r
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\n" ); document.write( "\n" ); document.write( " (the v0 is our constant of integration)\r
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\n" ); document.write( "\n" ); document.write( "Integrating again,\r
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\n" ); document.write( "\n" ); document.write( "And we are done.\r
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