document.write( "Question 6596: I am having dificulty solving logirithms once I put them in exponential form and vice versa. Here is the question I am confused on LOGx 16=4/3
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Algebra.Com's Answer #3628 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Convert this to exponential notation. \r
\n" ); document.write( "\n" ); document.write( "\"+log%28x%2C16%29+=4%2F3\" means that \"+x%5E%284%2F3%29+=+16\"\r
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\n" ); document.write( "\n" ); document.write( "What you really want is to have \"x%5E1\".\r
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\n" ); document.write( "\n" ); document.write( "In order to do this, raise both sides of the equation:
\n" ); document.write( "\"+x%5E%284%2F3%29+=+16\" to the \"3%2F4\" power:
\n" ); document.write( "\"+%28x%5E%284%2F3%29%29%5E%283%2F4%29+=+16%5E%283%2F4%29+\"\r
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\n" ); document.write( "\n" ); document.write( "From this you can see that
\n" ); document.write( "\"x+=+16%5E%283%2F4%29+\"
\n" ); document.write( "\"x+=+%28root%284%2C16%29%29%5E3\"
\n" ); document.write( "\"+x+=+2%5E3\"
\n" ); document.write( "\"x=8\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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