document.write( "Question 557745: ms. burke invested $27,000 in two account one yeilding 7% interest and the other 8%. If she received a total of $2,060 in interest at the end of the year, how much did she invest in each account? \n" ); document.write( "
Algebra.Com's Answer #362785 by mananth(16946)\"\" \"About 
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Investment I 7.00% per annum x
\n" ); document.write( "Investment II 8.00% per annum y
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\n" ); document.write( "x+y=27000 ------------------------1
\n" ); document.write( "7.00%x+ 8.00%y= $2,060.00
\n" ); document.write( "Multiply by 100
\n" ); document.write( "7x+8y=$206,000.00 --------2
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\n" ); document.write( "Multiply (1) by -7
\n" ); document.write( "we get
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\n" ); document.write( "-7x-7y= -189000.00
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( "y = $17,000.00 investment at 8.00%
\n" ); document.write( "Balance $10,000.00 investment at 7.00%
\n" ); document.write( "CHECK
\n" ); document.write( "$10,000.00 $700.00
\n" ); document.write( "$17,000.00 $1,360.00
\n" ); document.write( "Total $2,060.00
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