document.write( "Question 557691: ln(x+2)-ln(x-1)=1 \n" ); document.write( "

Algebra.Com's Answer #362768 by lwsshak3(11628) $\"\"$ $\"About$

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ln(x+2)-ln(x-1)=1
\n" ); document.write( "ln[x+2)/(x-1)]=1
\n" ); document.write( "convert to exponential form: base(e) raised to log of number(1)=number([x+2)/(x-1)])
\n" ); document.write( "e^1=[x+2)/(x-1)]=e
\n" ); document.write( "e(x-1)=x+2
\n" ); document.write( "ex-e=x+2
\n" ); document.write( "ex-x=e+2
\n" ); document.write( "x(e-1)=e+2
\n" ); document.write( "x=(e+2)/(e-1)
\n" ); document.write( "e≈2.71828.. \n" ); document.write( "

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