document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=557753>Question 557753</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve the following for x?<BR>\n" );
document.write( "log(base2)9 / log(base2)3 = log(base2)2x\r<BR>\n" );
document.write( "\n" );
document.write( "I tried : [log(base10) 9/log(base10)2]/[log(base10)3/log(base10)2] <BR>\n" );
document.write( "= log(base10)2x / log(base10)2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #362766 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=362766\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do I solve the following for x?<BR>\n" );
document.write( "log(base2)9 / log(base2)3 = log(base2)2x<BR>\n" );
document.write( "**<BR>\n" );
document.write( "log2(9)/log2(3)=log2(2x)<BR>\n" );
document.write( "log2(3^2)/log2(3)=log2(2x)<BR>\n" );
document.write( "2log2(3)/log2(3)=log2(2x)<BR>\n" );
document.write( "2=log2(2x)<BR>\n" );
document.write( "convert to exponential form: base(2) raised to log of number(2)=number(2x)<BR>\n" );
document.write( "2^2=2x<BR>\n" );
document.write( "4=2x<BR>\n" );
document.write( "x=2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );