document.write( "Question 557701: Hello i have a problem with the current problem. The problem is this:
\n" ); document.write( "Jen invested $6000, part at 10% and the rest at 5%. If the annual income from both investments was the same, find her total annual income from both investments.
\n" ); document.write( "The choices include:
\n" ); document.write( "A)$200
\n" ); document.write( "B)$250
\n" ); document.write( "C)$300
\n" ); document.write( "D)$350
\n" ); document.write( "E)$400
\n" ); document.write( "

Algebra.Com's Answer #362727 by Earlsdon(6294)\"\" \"About 
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If x = the amount Jen invested at 10%, then the remainder (6000-x) was invested at 5%. The earnings on these two amounts are equal, so...
\n" ); document.write( "0.1x = 0.05(6000-x) Simplify and solve for x.
\n" ); document.write( "0.1x = 300-0.05x Add 0.05x to both sides.
\n" ); document.write( "0.15x = 300 Divide both sides by 0.15
\n" ); document.write( "x = 2000 and 6000-x = 4000
\n" ); document.write( "The interest earned on the $2000 at 10% = 0.1(2000) = $200
\n" ); document.write( "The interest earned on the $4000 at 5% = 0.05(4000) = $200
\n" ); document.write( "The total interest earned = $400
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