document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54008>Question 54008</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My question is, if a bicyclist rode into the country for 5 h. Once returning, what was the speed if the person was traveling 5 mi/h faster and the trip took 4 h. What was the speed going each way? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36270 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36270\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=R*T THEN DISTANCE GOING IS R*5 AND THE SAME DISTANCE RETURNING IS (R+5)4 OR\r<BR>\n" );
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document.write( "5R=4(R+5) OR 5R=4R+20 OR R=20 MPH GOING  FOR 5 HOURS EQUALS 100 MILES.\r<BR>\n" );
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document.write( "THE RETURN TRIP WAS @ 25 MPH FOR 4 HOURS THUS 25*4=100 MILES.  </SPAN>\n" );
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