document.write( "Question 557651: A two-digit number is eight times the sim of its digits. When the number is added to the number obtained by reversing the digits, the sum is 99. Find the original number.\r
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document.write( "(I tried 10x+y=8(x+y), 10x+y+10y+x=99) It didn't work though...
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document.write( "Thanks! \n" );
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Algebra.Com's Answer #362699 by KMST(5328)![]() ![]() You can put this solution on YOUR website! Let tens digit be x and units digit be y. \n" ); document.write( "The value of the number is \n" ); document.write( "The sum of its digits is \n" ); document.write( "\"A two-digit number is eight times the sum of its digits\" translates into \n" ); document.write( " \n" ); document.write( "Since x and y are digits, the only solution is \n" ); document.write( "( \n" ); document.write( "So the number is 72. \n" ); document.write( "When you reverse the digits, you get 27, which added to 72 is 99, but why that was added to the problem is a mystery to me. \n" ); document.write( " |