document.write( "Question 557526: Another problem. Please help. My last question was nicely solved by stanbon(47716) and I salute you. the question is:-
\n" ); document.write( "When the expression a^+bx+c is divided by x-2, the remainder is R. When the expression is divided by x+1, the remainder is still R.
\n" ); document.write( " i.) Find the value of b.
\n" ); document.write( " ii.) When the expression is divided by x-4, the remainder is 2R. Find the value of c and R.
\n" ); document.write( "iii.) When the expression is divided by x-t, the remainder is 5R. Find the two possible values of t.
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Algebra.Com's Answer #362684 by KMST(5328)\"\" \"About 
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i.
\n" ); document.write( "I suspect you mean
\n" ); document.write( "\"When the expression C is divided by x-2, the remainder is R. When the expression is divided by x+1, the remainder is still R.\"
\n" ); document.write( "You have a quadratic trinomial \"P%28x%29=ax%5E2%2Bbx%2Bc\"
\n" ); document.write( "When you divide a polynomial P(x) by (x-a), the original polynomial, P(x), the quotient polynomial, Q(x), and the remainder R, are related through:
\n" ); document.write( "P(x)=Q(x)(x-a)+R (and P(a)=R).
\n" ); document.write( "So,
\n" ); document.write( "P(x)-R = Q(x)(x-a) is divisible by x-a.
\n" ); document.write( "In the case of your polynomial, P(x)-R is divisible by x-2 and by x+1.
\n" ); document.write( "So it is divisible by
\n" ); document.write( "\"%28x-2%29%28x%2B1%29=x%5E2-x-2\"
\n" ); document.write( "Then \"P%28x%29-R=ax%5E2%2Bbx%2Bc=a%28x-2%29%28x%2B1%29=a%28x%5E2-x-2%29=ax%5E2-ax-2a\" and
\n" ); document.write( "\"P%28x%29=a%28x-2%29%28x%2B1%29%2BR=ax%5E2-ax-2a%2BR\"
\n" ); document.write( "So \"b=-a\"
\n" ); document.write( "ii.
\n" ); document.write( "P(4) = \"a%284-2%29%284%2B1%29%2BR=10a%2BR=2R\"
\n" ); document.write( "\"10a%2BR=2R\" --> \"R=10a\"
\n" ); document.write( "\"c=-2a%2BR=-2a%2B10a=8a\"
\n" ); document.write( "iii.
\n" ); document.write( "P(t) = \"at%5E2-at%2B8a\" = \"5R\" = \"50a\"
\n" ); document.write( "\"at%5E2-at%2B8a=50a\" --> \"t%5E2-t-42a=0\"
\n" ); document.write( "Factoring, we get \"t%5E2-t-42a=%28t-7%29%28t%2B6%29\"
\n" ); document.write( "so \"%28t-7%29%28t%2B6%29=0\" has solutions \"t-7\" and \"t=-6\"
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