document.write( "Question 557354: could you please help me with this problem.\r
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document.write( "four times the complement of an angle less the supplemant of an angle is 27. find the angle\r
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document.write( "ive started\r
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document.write( " 4c-s=27\r
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document.write( "don't know if equation is right or if the awnser to it would be right \n" );
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Algebra.Com's Answer #362666 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! four times the complement of an angle less the supplement of an angle is 27. find the angle \n" ); document.write( ": \n" ); document.write( "let a = the angle \n" ); document.write( "when we know: \n" ); document.write( "(90-a) = the complement \n" ); document.write( "and \n" ); document.write( "(180-a) = the supplement \n" ); document.write( ": \n" ); document.write( "Now write the equation for the statement: \n" ); document.write( "\"four times the complement of an angle less the supplement of an angle is 27.\" \n" ); document.write( "4(90-a) - (180-a) = 27 \n" ); document.write( "360 - 4a - 180 + a = 27; change the sign of a when you remove the brackets \n" ); document.write( "-4a + a + 360 - 180 = 27 \n" ); document.write( "-3a + 180 = 27 \n" ); document.write( "-3a = 27 - 180 \n" ); document.write( "-3a = -153 \n" ); document.write( "a = \n" ); document.write( "a = +51 degrees is the angle \n" ); document.write( ": \n" ); document.write( "You can check this yourself, in the original equation \n" ); document.write( "4(90-51) - (180-51) = 27 \n" ); document.write( " |