document.write( "Question 557519: 2(3c+5) + 7(2c-1) = 3(4-8c)\r
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Algebra.Com's Answer #362640 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"2%283c%2B5%29%2B7%282c-1%29=3%284-8c%29\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"6c%2B10%2B14c-7=12-24c\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"20c%2B3=12-24c\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"20c=12-24c-3\" Subtract \"3\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"20c%2B24c=12-3\" Add \"24c\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"44c=12-3\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"44c=9\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"c=%289%29%2F%2844%29\" Divide both sides by \"44\" to isolate \"c\".\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"c=9%2F44\" \r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r
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