document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=557501>Question 557501</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this question:-<BR>\n" );
document.write( "1.) When polynomial ax^3+bx^2+cx-4 is divided by x+2 the remainder is double than obtained when the same polynomial is divided by x+1. Show that c can have any value and find b in terms of a. </SPAN>\n" );
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document.write( "1.) When polynomial ax^3+bx^2+cx-4 is divided by x+2 the remainder is double than obtained when the same polynomial is divided by x+1. <BR>\n" );
document.write( "----<BR>\n" );
document.write( "Find the remainders:<BR>\n" );
document.write( "f(-2) = -8a + 4b -2c -4<BR>\n" );
document.write( "----<BR>\n" );
document.write( "f(-1) = -a + b - c -4<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "f(-2) = 2f(-1)<BR>\n" );
document.write( "-8a + 4b -2c -4 = 2[-a+b-c-4]<BR>\n" );
document.write( "-8a + 4b -2c-4 = -2a + 2b -2c -8<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "6a -2b = 4<BR>\n" );
document.write( "3a - b = 2<BR>\n" );
document.write( "=======<BR>\n" );
document.write( "b = 3a-2<BR>\n" );
document.write( "c can be any value<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "==============\r<BR>\n" );
document.write( "\n" );
document.write( "Show that c can have any value and find b in terms of a. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );