document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=557477>Question 557477</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in planning her retirement, lliza deposits some money at 4% interest, with twice as much deposited at 4.5%. find the amount deposited at each rate in the total annual interest income is 2340. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #362625 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=362625\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If x = the smaller amount deposited and 2x = the larger amount, you can express the earnings on these two amounts, after converting the percentages to their decimal equivalents, as follows:<BR>\n" );
document.write( "0.04x+0.045(2x) = 2340 Simplify and solve for x.<BR>\n" );
document.write( "0.04x+0.09x = 2340<BR>\n" );
document.write( "0.13x = 2340<BR>\n" );
document.write( "x = 18000 and...<BR>\n" );
document.write( "2x = 36000<BR>\n" );
document.write( "So Lliza(?) deposited 18,000 (dollars or pounds or...?) at 4% interest and 36,000 at 4.5% interest.  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );