document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54015>Question 54015</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve each system by substitution     .5x-5y=19 and x-2y=-10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36261 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36261\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X-2Y=-10 OR X=2Y-10 NOW SUBSTITUTING (2Y-10) FOR X IN THE OTHER EQUATION WE GET  .5(2Y-10)-5Y=19 OR Y-5-5Y=19 OR -4Y=24 OR Y=24/-4 OR Y=-6 \r<BR>\n" );
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document.write( "THE X-2(-6)=-10 OR X+12=-10 OR X=-10-12 OR X=-22\r<BR>\n" );
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document.write( "PROOF .5(-22)-5*-6=19 OR -11+30=19 OR 19=19 </SPAN>\n" );
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