document.write( "Question 557420: find two numbers whose sum is 12 and whose difference between their squares is 48 \n" ); document.write( "

Algebra.Com's Answer #362601 by rajagopalan(174) $\"\"$ $\"About$

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sum is 12
\n" ); document.write( "difference between their squares is 48
\n" ); document.write( "let the numbers be x and y
\n" ); document.write( "we form eqn 1 with x+y=12
\n" ); document.write( "we form eqn 2 with (x^2-y^2)=48 or (x+y)*(x-y)=48
\n" ); document.write( "divide eqn 2 by eqn 1
\n" ); document.write( "we get (x+y)*(x-y)/(x+y)=(x-y)=48/12=4
\n" ); document.write( "x+y=12...eqn 1
\n" ); document.write( "x-y=4....eqn 3
\n" ); document.write( "adding eqns 1 and 3 we get 2x=16
\n" ); document.write( "x=16/2=8
\n" ); document.write( "naturally y=4
\n" ); document.write( "verify X^2-Y^2=64-16=48 ok
\n" ); document.write( "cheers
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