document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=557289>Question 557289</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 5 more than twice another number. The sum of the numbers is 35. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #362577 by </B><A HREF=/tutors/aboutme.mpl?userid=bluemockingjay7><B>bluemockingjay7(41)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bluemockingjay7><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=bluemockingjay7><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=362577\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1st number = x<BR>\n" );
document.write( "2nd number = 2x + 5<BR>\n" );
document.write( "sum = 35\r<BR>\n" );
document.write( "\n" );
document.write( "x + 2x + 5 = 35<BR>\n" );
document.write( "3x + 5 = 35<BR>\n" );
document.write( "3x = 35 - 5<BR>\n" );
document.write( "3x = 30<BR>\n" );
document.write( "3x/3 = 30/3<BR>\n" );
document.write( "x = 10\r<BR>\n" );
document.write( "\n" );
document.write( "1st number = 10<BR>\n" );
document.write( "2nd number = 2(10) + 5 = 20 + 5 = 25 </SPAN>\n" );
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