document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=557358>Question 557358</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two angles are supplementary and the larger is 20 degree less than the three times the smaller.Find the angles<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #362568 by </B><A HREF=/tutors/aboutme.mpl?userid=bluemockingjay7><B>bluemockingjay7(41)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bluemockingjay7><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=bluemockingjay7><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=362568\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> supplementary = 180 degrees<BR>\n" );
document.write( "larger = 3x - 20<BR>\n" );
document.write( "smaller = x\r<BR>\n" );
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document.write( "3x - 20 + x = 180<BR>\n" );
document.write( "4x - 20 = 180<BR>\n" );
document.write( "4x = 180 + 20<BR>\n" );
document.write( "4x = 200<BR>\n" );
document.write( "4x/4 = 200/4<BR>\n" );
document.write( "x = 50\r<BR>\n" );
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document.write( "smaller = 50 degrees<BR>\n" );
document.write( "larger = 3(50) - 20 = 150 - 20 = 130 degrees </SPAN>\n" );
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