document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=557322>Question 557322</A>: <I><SPAN STYLE=\"word-break: break-all;\"> three times the complement of an angle less the suppliment of an angle is 10 decrees. find the suppliment </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #362558 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=362558\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> three times the complement of an angle less the suppliment of an angle is 10 decrees. find the supplement<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "angle: x<BR>\n" );
document.write( "complement: 90-x<BR>\n" );
document.write( "supplement: 180-x<BR>\n" );
document.write( "-------------------------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "3(90-x)-(180-x) = 10<BR>\n" );
document.write( "270-3x-180+x = 10<BR>\n" );
document.write( "-2x +90 = 10<BR>\n" );
document.write( "-2x = -80<BR>\n" );
document.write( "x = 40<BR>\n" );
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document.write( "supplement: 180-x = 180-40 = 140 degrees<BR>\n" );
document.write( "=============================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "==================<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );