document.write( "Question 557241: Tina hiked 15 km up a mountain trail. Her return trip along the same trail took 1/2 hour less, because she increased her speed by 1 km/hr. How long did it take her to climb up and down the trail? \n" ); document.write( "
Algebra.Com's Answer #362553 by ankor@dixie-net.com(22740)\"\" \"About 
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Tina hiked 15 km up a mountain trail.
\n" ); document.write( "Her return trip along the same trail took 1/2 hour less, because she increased her speed by 1 km/hr.
\n" ); document.write( "How long did it take her to climb up and down the trail?
\n" ); document.write( ":
\n" ); document.write( "Let t = time down the trail
\n" ); document.write( "then
\n" ); document.write( "(t+.5) = up the trail
\n" ); document.write( ":
\n" ); document.write( "Write a speed equation: Speed = dist/time
\n" ); document.write( ":
\n" ); document.write( "speed down - speed up = 1 km/h
\n" ); document.write( "\"15%2Ft\" - \"15%2F%28%28t%2B.5%29%29\" = 1
\n" ); document.write( "Multiply eq by t(t+.5), results:
\n" ); document.write( "15(t+.5) - 15t = t(t+.5)
\n" ); document.write( "15t + 7.5 - 15t = t^2 + .5t
\n" ); document.write( "A quadratic equation from this
\n" ); document.write( "0 = t^2 + .5t - 7.5
\n" ); document.write( "You can use the quadratic formula but this will factor
\n" ); document.write( "(t-2.5)(t+3) = 0
\n" ); document.write( ":
\n" ); document.write( "t = 2.5 hrs; is the time down the hill
\n" ); document.write( "then
\n" ); document.write( "2.5 + .5 = 3 hr; is the time up the hill
\n" ); document.write( ";
\n" ); document.write( "Check this by finding the speeds:
\n" ); document.write( "15/2.5 = 6 km/h down the hill
\n" ); document.write( "15/3 = 5 km/h up the hill\r
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