document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=557140>Question 557140</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find an expression for the area of a triangle with base (4a+3) and perpendicular height (6a-2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #362472 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=362472\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find an expression for the area of a triangle with base (4a+3) and perpendicular height (6a-2)<BR>\n" );
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document.write( "Area = (1/2)(base)(height)<BR>\n" );
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document.write( "A = (1/2)(6a-2)(4a+3)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "A = (3a-1)(4a+3)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "A = 12a^2+9a-4a-3<BR>\n" );
document.write( "----<BR>\n" );
document.write( "A = 12a^2+5a-3<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "==================== </SPAN>\n" );
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