document.write( "Question 53951: tickets for a train $120 for sleeping room $80 for berth and $50 for coach the total sales were $8600 If there were 20 more berth than sleeping and 3 time as many coach as sleeping how many of each type were sold. I am just having problem with the formula after i get that i can keep going i cant get if its x+2(c)=8600 Or c(x+2)=8600 even then i can figure it out after that there must be something with the amounts or its a two part problem just get me the 1st step Thanks \n" ); document.write( "
Algebra.Com's Answer #36246 by ankor@dixie-net.com(22740)\"\" \"About 
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tickets for a train $120 for sleeping room $80 for berth and $50 for coach
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\n" ); document.write( "the total sales were $8600
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\n" ); document.write( "Let s = no. of sleeping rms; Let b = no. of berths; Let c = no. of coaches
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\n" ); document.write( "If there were 20 more berth than sleeping
\n" ); document.write( " b = s + 20
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\n" ); document.write( " and 3 time as many coach as sleeping
\n" ); document.write( " c = 3s
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\n" ); document.write( " how many of each type were sold.
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\n" ); document.write( " 120s + 80b + 50c = 8600
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\n" ); document.write( "Substitute (s+20) for b; and 3s for c; in above eq, and solve for s
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\n" ); document.write( "This should help you.\r
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