document.write( "Question 557050: The sum of three numbers is 100. The second number is 2 more than three times the first number, and the third number is the sum of the first two numbers. what are the numbers? \n" ); document.write( "
Algebra.Com's Answer #362404 by Earlsdon(6294)\"\" \"About 
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Let the three numbers be: a, b, and c.
\n" ); document.write( "b = 3a+2 \"The second number is 2 more than 3 times the first number.\"
\n" ); document.write( "c = a+b \"The third number is the sum of the first two numbers.\"
\n" ); document.write( "a+b+c = 100 \"The sum of three numbers is 100.\" Substitute b = 3a+2.
\n" ); document.write( "a+(3a+2)+c = 100 Substitute c = a+b and b = 3a+2.
\n" ); document.write( "a+(3a+2)+a+3a+2 = 100 Simplify.
\n" ); document.write( "8a+4 = 100 Subtract 4 from both sides.
\n" ); document.write( "8a = 96 Divide both sides by 8.
\n" ); document.write( "a = 12
\n" ); document.write( "b = 3(12)+2
\n" ); document.write( "b = 38
\n" ); document.write( "c = 12+38
\n" ); document.write( "c = 50
\n" ); document.write( "Check:
\n" ); document.write( "a+b+c = 12+38+50 = 100
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