document.write( "Question 557050: The sum of three numbers is 100. The second number is 2 more than three times the first number, and the third number is the sum of the first two numbers. what are the numbers? \n" ); document.write( "
Algebra.Com's Answer #362404 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Let the three numbers be: a, b, and c. \n" ); document.write( "b = 3a+2 \"The second number is 2 more than 3 times the first number.\" \n" ); document.write( "c = a+b \"The third number is the sum of the first two numbers.\" \n" ); document.write( "a+b+c = 100 \"The sum of three numbers is 100.\" Substitute b = 3a+2. \n" ); document.write( "a+(3a+2)+c = 100 Substitute c = a+b and b = 3a+2. \n" ); document.write( "a+(3a+2)+a+3a+2 = 100 Simplify. \n" ); document.write( "8a+4 = 100 Subtract 4 from both sides. \n" ); document.write( "8a = 96 Divide both sides by 8. \n" ); document.write( "a = 12 \n" ); document.write( "b = 3(12)+2 \n" ); document.write( "b = 38 \n" ); document.write( "c = 12+38 \n" ); document.write( "c = 50 \n" ); document.write( "Check: \n" ); document.write( "a+b+c = 12+38+50 = 100 \n" ); document.write( " |