document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=53993>Question 53993</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395937787/algebrahomeworkh>McDougal Littel Algebra 2</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I've been trying to figure out how to do this problem but I can't seem to get it right.  The problem is...<BR>\n" );
document.write( "Solve the system using any algebraic method<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%2By%2B2z=7 ALIGN=MIDDLE  ALT=\"2x%2By%2B2z=7\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x-y%2B2z=1 ALIGN=MIDDLE  ALT=\"2x-y%2B2z=1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5x%2By%2B5z=13 ALIGN=MIDDLE  ALT=\"5x%2By%2B5z=13\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "I tried the problem a couple of times but I still couldn't get the answer right.<BR>\n" );
document.write( "This is what I tried:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%2By%2B2z=7 ALIGN=MIDDLE  ALT=\"2x%2By%2B2z=7\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x-y%2B2z=1 ALIGN=MIDDLE  ALT=\"2x-y%2B2z=1\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "and that cancelled out the y value and left me with 4x+4z=8.  Then I combined <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x-y%2B2z=1 ALIGN=MIDDLE  ALT=\"2x-y%2B2z=1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5x%2By%2B5z=13 ALIGN=MIDDLE  ALT=\"5x%2By%2B5z=13\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "that cancelled out the y value again and left 7x+7z=14 and from there I got stuck. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36239 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36239\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2X+Y+2Z=7<BR>\n" );
document.write( "2X-Y+2Z=1 A BETTER MOVE HERE IS TO SUBTRACT THE SECOND EQUATION FROM THE FIRST<BR>\n" );
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document.write( "2Y=6 OR Y=6/2 OR Y=3 2X+3+2Z=7 OR 2X+2Z=4 & 2X-3+2Z=1 OR 2X+2Z=4 OR X+Z=2\r<BR>\n" );
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document.write( "THEN X & Z  CAN EQUAL 1 & 1 OR X & Z CAN EQUAL 3 & -1 OR X & Z CAN EQUAL <BR>\n" );
document.write( "4 & -2 OR ANY OTHER COMBINATION THAT=2   </SPAN>\n" );
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