document.write( "Question 556944: The perimeter of a rectangle is 50ft. The lenght is 9 more than the width. Find the legnth and width \n" ); document.write( "
Algebra.Com's Answer #362344 by JBarnum(2146)\"\" \"About 
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p=50
\n" ); document.write( "50=2(l+w)
\n" ); document.write( "l=9+w
\n" ); document.write( "50=2(9+w+w)
\n" ); document.write( "50=18+4w
\n" ); document.write( "32=4w
\n" ); document.write( "8=w
\n" ); document.write( "17=l
\n" ); document.write( "
\n" );