document.write( "Question 556944: The perimeter of a rectangle is 50ft. The lenght is 9 more than the width. Find the legnth and width \n" ); document.write( "
Algebra.Com's Answer #362344 by JBarnum(2146)![]() ![]() You can put this solution on YOUR website! p=50 \n" ); document.write( "50=2(l+w) \n" ); document.write( "l=9+w \n" ); document.write( "50=2(9+w+w) \n" ); document.write( "50=18+4w \n" ); document.write( "32=4w \n" ); document.write( "8=w \n" ); document.write( "17=l \n" ); document.write( " |