document.write( "Question 556915: The length of the rectangle is three times the width. The area is 48. Find the length, width, and perimeter \n" ); document.write( "
Algebra.Com's Answer #362324 by JBarnum(2146)![]() ![]() You can put this solution on YOUR website! l=length w=width p=perimeter a=area \n" ); document.write( "given: \n" ); document.write( "lw=a \n" ); document.write( "l=3w \n" ); document.write( "a=48 \n" ); document.write( "p=2(l+w) \n" ); document.write( "p=8w \n" ); document.write( ". \n" ); document.write( "substitution work: \n" ); document.write( "48=3w(w) \n" ); document.write( "48=3w^2 \n" ); document.write( "16=w^2 \n" ); document.write( "4=w \n" ); document.write( "l=12 \n" ); document.write( ". \n" ); document.write( "p=8(4) \n" ); document.write( "p=32 \n" ); document.write( " |