document.write( "Question 556915: The length of the rectangle is three times the width. The area is 48. Find the length, width, and perimeter \n" ); document.write( "
Algebra.Com's Answer #362324 by JBarnum(2146)\"\" \"About 
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l=length w=width p=perimeter a=area
\n" ); document.write( "given:
\n" ); document.write( "lw=a
\n" ); document.write( "l=3w
\n" ); document.write( "a=48
\n" ); document.write( "p=2(l+w)
\n" ); document.write( "p=8w
\n" ); document.write( ".
\n" ); document.write( "substitution work:
\n" ); document.write( "48=3w(w)
\n" ); document.write( "48=3w^2
\n" ); document.write( "16=w^2
\n" ); document.write( "4=w
\n" ); document.write( "l=12
\n" ); document.write( ".
\n" ); document.write( "p=8(4)
\n" ); document.write( "p=32
\n" ); document.write( "
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