document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=556820>Question 556820</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 75 litres cost £1000 what does 1 litre cost\r<BR>\n" );
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document.write( "regards<BR>\n" );
document.write( "Sarah </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #362245 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=362245\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i believe the symbol is for british pounds.<BR>\n" );
document.write( "i'll assume that and you can make adjutments to whatever unit you are referring to accordingly.<BR>\n" );
document.write( "75 liters cost 1000 british pounds.<BR>\n" );
document.write( "1 liter will cost 1000/75 = 40/3 british pounds.<BR>\n" );
document.write( "algebraically you would solve as follows:<BR>\n" );
document.write( "let L represent 1 liter.<BR>\n" );
document.write( "let P represent 1 pound.<BR>\n" );
document.write( "your equation is:<BR>\n" );
document.write( "75 * L = 1000 * P<BR>\n" );
document.write( "divide both sides of this equation to gt:<BR>\n" );
document.write( "L = (1000/75) * P<BR>\n" );
document.write( "simplify to get:<BR>\n" );
document.write( "L = (40/3) * P<BR>\n" );
document.write( "that's equivalent to 13 and 1/3 pounds which has a decimal equivalent of 13.333333 pounds which you can round to the nearest decimal point of your choice.<BR>\n" );
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