document.write( "Question 556489: How do I solve this? I think it's with solving by logs but I can't get the right answer.
\n" ); document.write( "6(2^(3x-1))-7=9
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Algebra.Com's Answer #362179 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+6%2A%28+2%5E%283x+-+1%29%29+-+7+=+9+\"
\n" ); document.write( "\"+6%2A%28+2%5E%283x+-+1%29%29+=+16+\"
\n" ); document.write( "\"+2%5E%283x+-+1%29+=+16%2F6+\"
\n" ); document.write( "\"+2%5E%283x+-+1%29+=+8%2F3+\"
\n" ); document.write( "On my calculator, I found
\n" ); document.write( "\"+log%282%2C3%29+=+1.585+\"
\n" ); document.write( "I can now say
\n" ); document.write( "\"+2%5E1.585+=+3+\"
\n" ); document.write( "and
\n" ); document.write( "\"+2%5E%283x+-+1%29+=+2%5E3+%2F+2%5E1.585+\"
\n" ); document.write( "\"+2%5E%283x+-+1%29+=+2%5E1.415+\"
\n" ); document.write( "\"+3x+-+1+=+1.415+\"
\n" ); document.write( "\"+3x+=+2.415+\"
\n" ); document.write( "\"+x+=+.805+\"
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