document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=53979>Question 53979</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The second of two numbers is 3 more than the first. If 4 times the first is increased by the second, the result is 73. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36216 by </B><A HREF=/tutors/aboutme.mpl?userid=funmath><B>funmath(2933)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=funmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36216\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the 1st number=x<BR>\n" );
document.write( "Then the 2nd number=x+3<BR>\n" );
document.write( "4 times (4*) the first number (x) increased by (+) the second number (x+3)the result is (=) 73.<BR>\n" );
document.write( "4(x)+(x+3)=73<BR>\n" );
document.write( "4x+x+3=73<BR>\n" );
document.write( "5x+3=73<BR>\n" );
document.write( "5x+3-3=73-3<BR>\n" );
document.write( "5x=70<BR>\n" );
document.write( "5x/5=70/5<BR>\n" );
document.write( "x=14<BR>\n" );
document.write( "The first number:x=14<BR>\n" );
document.write( "The second number:x+3=14+3=17<BR>\n" );
document.write( "Happy calculating!!! </SPAN>\n" );
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