document.write( "Question 556128: I have a few similar questions, so I preferred submitting them in a single question rather than in a different one. I hope that is alright.\r
\n" ); document.write( "\n" ); document.write( "1. What annual rate compounded continuously is equivalent to an effective rate of 5%?\r
\n" ); document.write( "\n" ); document.write( "2. What annual rate r compounded continuously is equivalent to a nominal rate if 6% compounded semi-annually?\r
\n" ); document.write( "\n" ); document.write( "3. If interest is compounded continuously at an annual rate of 0.07, how many years would it take for a principal P o triple? Give your answer to the nearest year.\r
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Algebra.Com's Answer #362103 by ankor@dixie-net.com(22740)\"\" \"About 
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1. What annual rate compounded continuously is equivalent to an effective rate of 5%?
\n" ); document.write( "Continuous interest formula: \"A+=+P%2Ae%5E%28rt%29\" for 1 yr: \"A+=+P%2Ae%5Er\"
\n" ); document.write( "Simple interest formula for 1 yr: A = P*(1+r)
\n" ); document.write( "A simple equation
\n" ); document.write( "\"e%5Er\" = 1.05
\n" ); document.write( "Find the nat log of both sides (nat log of e = 1)
\n" ); document.write( "r = ln(1.05)
\n" ); document.write( "r = .04879 ~ 4.88% cont interest is equiv to 5% simple int for 1 yr
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\n" ); document.write( "2. What annual rate r compounded continuously is equivalent to a nominal rate if 6% compounded semi-annually?
\n" ); document.write( "Compounded semi annually: (1.03)^2 = 1.0609
\n" ); document.write( "\"e%5Er\" = 1.0609
\n" ); document.write( "r = ln(1.0609)
\n" ); document.write( "r = .0591 ~ 5.91% cont interest
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\n" ); document.write( "3. If interest is compounded continuously at an annual rate of 0.07, how many years would it take for a principal P to triple?
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\n" ); document.write( "\"e%5E%28.07t%29\" = 3
\n" ); document.write( ".07t = ln(3)
\n" ); document.write( ".07t = 1.0986
\n" ); document.write( "t = \"1.0986%2F.07\"
\n" ); document.write( "t = 15.7 ~ 16 yrs to triple
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