document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=556268>Question 556268</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I don't have a clue or where to begin solving\r<BR>\n" );
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document.write( "5a - 2b - 3c = 10<BR>\n" );
document.write( "     5b - 2c = -4<BR>\n" );
document.write( "           c = 3\r<BR>\n" );
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document.write( "Please help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #362101 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=362101\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> substituting the value of c ___ 5b - 2(3) = -4 ___ 5b = 2 ___ b = .4\r<BR>\n" );
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document.write( "substituting the values of c and b ___ 5a - 2(.4) - 3(3) = 10 ___ 5a = 19.8 ___ a = 3.96 </SPAN>\n" );
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