document.write( "Question 556223: An antique dealer bought c antique chairs for a total of x dollars. the dealer sold each chair for y dollars. write an algebraic expression for profit, P, earned from buying and selling the chairs.
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document.write( "write algebraic expression for the profit per chair. \n" );
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Algebra.Com's Answer #362094 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the cost per chair is equal to x/c. \n" ); document.write( "the revenue per chair is equal to y. \n" ); document.write( "let p equal the profit per chair. \n" ); document.write( "p = revenue per chair minus cost per chair which becomes: \n" ); document.write( "p = r - x/c \n" ); document.write( "total profit equals total revenue minus total cost. \n" ); document.write( "total profit = p*c \n" ); document.write( "total revenue = y*c \n" ); document.write( "total cost = x \n" ); document.write( "equation becomes: \n" ); document.write( "p*c = y*c - x \n" ); document.write( "p = profit per chair \n" ); document.write( "p*c = total profit. \n" ); document.write( "here's how it would work. \n" ); document.write( "assume c = 50 = number of chairs \n" ); document.write( "assume x = 5,000 = total cost \n" ); document.write( "assume y = 200 = revenue per chair. \n" ); document.write( "profit per chair = p = 200 - 5,000/50 = 200 - 100 = 100 \n" ); document.write( "total profit = p*c = y*c - x = 200*50 - 5,000 = 10,000 - 5,00 = 5,000 \n" ); document.write( "you have: \n" ); document.write( "p*c = 5,000 \n" ); document.write( "p = 100 \n" ); document.write( "c = 50 \n" ); document.write( "equation becomes: \n" ); document.write( "5,000 = 5,000 \n" ); document.write( "this confirms the equations are good.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |