document.write( "Question 556203: I do not know if I placed this question in the right category, but I cannot figure it out at all! here it is:\r
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document.write( "Find all values for x for which x-3/x+4 is greater than or equal to x+2/x-5...write in interval notation... \n" );
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Algebra.Com's Answer #362084 by Theo(13342)![]() ![]() You can put this solution on YOUR website! you start with (x-3)/(x+4) >= (x+2)/(x-5) \n" ); document.write( "subtract (x+2)/(x-5) from both sides of the equation to get: \n" ); document.write( "(x-3)/(x+4) - (x+2)/(x-5) >= 0 \n" ); document.write( "x cannot be equal to -4 nor can it be equal to 5 because when it is those values, the equation becomes undefined since you can't divide by 0. \n" ); document.write( "it appears that this equation will have asymptotes at those values of x. \n" ); document.write( "here's a graph of the equation. \n" ); document.write( " \n" ); document.write( "it appears that the graph is greater than or equal to 0 when: \n" ); document.write( "x < -4 \n" ); document.write( "1/2 <= x < 5 \n" ); document.write( "this means that (x-3)/(x+4) >= (x+2)/(x-5) when x < -4 and when 1/2 <= x < 5. \n" ); document.write( "it can be seen easily by graphing the equation. \n" ); document.write( "it's not so simple to solve algebraically as i found out much to my dismay. \n" ); document.write( "in fact, if i didn't graph it, i would probably not have been able to solve it unless i knew how to solve problems like this from previous experience. \n" ); document.write( "now that i did graph it, however, i could see what was happening and then able to provide an algebraic explanation for the answer. \n" ); document.write( "i examined the original equation and determined that the equation was undefined at x = -4 and x = 5. \n" ); document.write( "i would have needed to test if there were asymptotes at those locations. \n" ); document.write( "that test would have required substituting values of -4.1 and -3.9 and 4.9 and 5.1 for x to see what the values of y were at those points. that would have shown that the asymptote existed at x = -4 and x = 5. \n" ); document.write( "i would then have had to test for a zero point of the equation by setting the equation equal to 0. \n" ); document.write( "that would have yielded a zero point at x = 1/2 \n" ); document.write( "i would then have tested the equation when x < -4 to see that it was positive. \n" ); document.write( "that would have led to the conclusion that (x-3)/(x+4) >= (x+2)/(x-5) was true when x < -4. \n" ); document.write( "i would then have tested the equation when x > -4 and < 1/2. \n" ); document.write( "that would have led to the conclusion that (x-3)/(x+4) >= (x+2)/(x-5) was false during that interval. \n" ); document.write( "i would then have tested the equation when x >= 1/2 and < 5. that would have led to the conclusion that (x-3)/(x+4) >= (x+2)/(x-5) was true when x >= 1/2 and < 5 \n" ); document.write( "i would then have tested the equation when x > 5. that would have led to the conclusion that (x-3)/(x+4) >= (x+2)/(x-5) was false when x > 5. \n" ); document.write( "it's a lot of work. \n" ); document.write( "graphing the equation was so much easier and allowed me to see what was happening right away. \n" ); document.write( "the only thing i needed to know was how to graph the equation. \n" ); document.write( "the original equation was: \n" ); document.write( "(x-3)/(x+4) >= (x+2)/(x-5) \n" ); document.write( "i subtracted (x+2)/(x-5) from both sides of the equation to get: \n" ); document.write( "(x-3)/(x+4) - (x+2)/(x-5) >= 0 \n" ); document.write( "i then set the expression on the left side of that equation equal to y to get: \n" ); document.write( "y = (x-3)/(x+4) - (x+2)/(x-5) \n" ); document.write( "this is the equation that i graphed. \n" ); document.write( "the rest was just looking and seeing where the equation was positive and where it was not, keeping in mind the asymptotes at x = -4 and x = 5. \n" ); document.write( "the basic logic used was: \n" ); document.write( "if a >= b, then (a - b) >= 0\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |