document.write( "Question 556073: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 mph and train B is traveling at 110 mph. Train A passes a station at 4:20 AM. If train B passes the same station at 4:50 AM, what time will train B catch up to train A? \n" ); document.write( "

Algebra.Com's Answer #362080 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Trains A and B are traveling in the same direction on parallel tracks.
\n" ); document.write( "Train A is traveling at 100 mph and train B is traveling at 110 mph.
\n" ); document.write( " Train A passes a station at 4:20 AM.
\n" ); document.write( " If train B passes the same station at 4:50 AM, what time will train B catch up to train A?
\n" ); document.write( ":
\n" ); document.write( "From the given information, we know that Train B is 30 min behind A at at 4:20AM
\n" ); document.write( "therefore Train B is:
\n" ); document.write( " $\"30%2F60\"$ * 110 = 55 miles behind Train A at that time.
\n" ); document.write( ":
\n" ); document.write( "Let t = time required for Train B to catch Train A
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation; dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "Train B dist = Train A dist + 24 mi
\n" ); document.write( "110t = 100t + 55
\n" ); document.write( "110t - 100t = 55
\n" ); document.write( "10t = 55
\n" ); document.write( "t = $\"55%2F10\"$
\n" ); document.write( "t = 5.5 hrs for B to catch A
\n" ); document.write( ":
\n" ); document.write( "Convert 5.5 hrs to hrs and minutes: 5 hrs 30 min
\n" ); document.write( ":
\n" ); document.write( "Find the time from 4:20 am:
\n" ); document.write( "4:20 + 5:30 = 9:50 am Train B catches Train A \n" ); document.write( "

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