document.write( "Question 544114: [2x+3]> 17\r
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document.write( "with > being greater than or equal to. Please help me I have midterm exam coming up! \n" );
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Algebra.Com's Answer #362056 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! [2x+3]≥ 17 \n" ); document.write( "solve for two conditions: \n" ); document.write( "for (2x+3)>0 \n" ); document.write( "2x+3≥ 17 \n" ); document.write( "2x≥14 \n" ); document.write( "x≥7 \n" ); document.write( ".. \n" ); document.write( "for (2x+3)<0 \n" ); document.write( "-2x-3≥ 17 \n" ); document.write( "-2x≥20 \n" ); document.write( "divide by -2 and reverse inequality sign \n" ); document.write( "x≤-10 \n" ); document.write( ".. \n" ); document.write( "number line: \n" ); document.write( "<===-10].......[7===> \n" ); document.write( "solution: \n" ); document.write( "(-∞,-10] U [7,∞) \n" ); document.write( " |