document.write( "Question 544114: [2x+3]> 17\r
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\n" ); document.write( "\n" ); document.write( "with > being greater than or equal to. Please help me I have midterm exam coming up!
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Algebra.Com's Answer #362056 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
[2x+3]≥ 17
\n" ); document.write( "solve for two conditions:
\n" ); document.write( "for (2x+3)>0
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\n" ); document.write( "2x≥14
\n" ); document.write( "x≥7
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\n" ); document.write( "for (2x+3)<0
\n" ); document.write( "-2x-3≥ 17
\n" ); document.write( "-2x≥20
\n" ); document.write( "divide by -2 and reverse inequality sign
\n" ); document.write( "x≤-10
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\n" ); document.write( "number line:
\n" ); document.write( "<===-10].......[7===>
\n" ); document.write( "solution:
\n" ); document.write( "(-∞,-10] U [7,∞)
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